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We will complete our determination of the Fourier series solution of the heat equation as presented in the previous lecture. This was the problem of: ut=κuxx,x∈[0,π],t≥0u(0,t)=0=u(π,t)u(x,0)=f(x)=1.
u(x,t)∼∞∑1[bnsin(nπxL)].
where bn will be the Fourier sine coefficients of the odd 2π extension of f(x) on [0,π].
Solution of 1D heat equation with zero Dirichlet
- % Written for MA20223 Vectors & PDEs
- clear % Clear all variables
- close all % Close all windows
- N = 20; % How many Fourier modes to include?
- % Define an in-line function that takes in three inputs:
- % Input 1: n value [scalar]
- % Input 2: x value [vector]
- % Input 3: t value [scalar]
- R = @(n, t, x) -2/(n*pi)*((-1)^n - 1)*exp(-n^2*t)*sin(n*x);
- % Create a mesh of points between two limits
- x0 = pi;
- x = linspace(0, x0, 1000);
- % Create a mesh of points in time
- t = linspace(0, 5, 200);
- figure(1); % Open the figure
- plot([0, pi], [1, 1], 'b', 'LineWidth', 2); % Plot the base function
- ylim([-0.2,1.2]); % Set the y limits
- xlim([0, x0]); % Set the x limits
- xlabel('x'); ylabel('u(x,t)');
- hold on
- for j = 1:length(t)
- tj = t(j);
- u = 0;
- for n = 1:N
- u = u + R(n, tj, x);
- end
- % Plotting commands
- if j == 1
- p = plot(x, u, 'r');
- else
- set(p, 'YData', u);
- end
- drawnow
- title(['t = ', num2str(tj)]);
- pause(0.1);
- if j == 1
- pause
- end
- end